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Re: [noreply@xxxxxxxxxxxxx: [Branch ~cbc-core/cbc.solve/main] Rev 99: Fixed auto time-step size corrector when T is a multiple of dt]

 

On Tue, Apr 13, 2010 at 02:42:34PM +0200, Harish Narayanan wrote:
> On 4/13/10 1:32 PM, Anders Logg wrote:
> > What if T = 10 and dt = 0.9999999999. Then we get
> >
> >   ceil(T / dt) = 11.
>
> I am not sure I understand what is wrong with this.
>
> If dt = 1.0, then we get 10 time steps. If dt < 1.0, we get more time steps.
>
> Harish

Isn't there a chance that one might specify the time step to be k and
the end time to be n*k and get T / k = n + eps?

--
Anders

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