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Re: [noreply@xxxxxxxxxxxxx: [Branch ~cbc-core/cbc.solve/main] Rev 99: Fixed auto time-step size corrector when T is a multiple of dt]

To: Anders Logg <logg@xxxxxxxxx>
From: Harish Narayanan <harish.mlists@xxxxxxxxx>
Date: Tue, 13 Apr 2010 14:42:34 +0200
Cc: CBC Mailing List <cbc@xxxxxxxxxxxxxxxxxxx>
In-reply-to: <20100413113206.GB8770@olorin>
User-agent: Industrious bit-pushing elves

On 4/13/10 1:32 PM, Anders Logg wrote:
> What if T = 10 and dt = 0.9999999999. Then we get
> 
>   ceil(T / dt) = 11.

I am not sure I understand what is wrong with this.

If dt = 1.0, then we get 10 time steps. If dt < 1.0, we get more time steps.

Harish

Follow ups

Re: [noreply@xxxxxxxxxxxxx: [Branch ~cbc-core/cbc.solve/main] Rev 99: Fixed auto time-step size corrector when T is a multiple of dt]
From: Anders Logg, 2010-04-13

References

[noreply@xxxxxxxxxxxxx: [Branch ~cbc-core/cbc.solve/main] Rev 99: Fixed auto time-step size corrector when T is a multiple of dt]
From: Anders Logg, 2010-04-13